A bag contains 3 red, 2 blue, and 5 green balls. If you draw one ball, what is the probability it is blue?

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Multiple Choice

A bag contains 3 red, 2 blue, and 5 green balls. If you draw one ball, what is the probability it is blue?

Explanation:
Probability is found by comparing how many favorable outcomes there are to how many total outcomes are possible, assuming every ball is equally likely to be drawn. There are 3 red, 2 blue, and 5 green balls, so total balls = 10. The favorable outcomes (drawing blue) = 2. So the probability is 2/10, which simplifies to 1/5. That means the chance of drawing a blue ball is 1/5 (0.2). The other fractions don’t match the actual counts: 1/3 would need 3 blue out of 9, 2/5 would need 4 blue out of 10, and 1/2 would need 5 blue out of 10.

Probability is found by comparing how many favorable outcomes there are to how many total outcomes are possible, assuming every ball is equally likely to be drawn. There are 3 red, 2 blue, and 5 green balls, so total balls = 10. The favorable outcomes (drawing blue) = 2. So the probability is 2/10, which simplifies to 1/5. That means the chance of drawing a blue ball is 1/5 (0.2). The other fractions don’t match the actual counts: 1/3 would need 3 blue out of 9, 2/5 would need 4 blue out of 10, and 1/2 would need 5 blue out of 10.

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